The value of each brick is the sum of the two bricks below it. Can you work out the value of each brick?
CLICK ON EACH BRICK TO REVEAL ITS VALUE.
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Although some logical reasoning will be required, little assistance will be needed to solve Addition Walls up to 'Normal'. However, 'Tough' and 'Fiendish' provide a very different challenge. In the example below, pupils can of course use trial and improvement. However, another way you could address this would be to ask pupils to consider how many times each box on the bottom row is used to make the numbers 33 and 40.
In the example below, we derive the value B by adding (10 + A) and C by adding (A+9). Because we know that B+C=33, we therefore know that 10+A added to A+9 (or 2A+19), will give us the total 33. Once we know this, we can work out that 2A = 14, and therefore that A = 7.
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